{"id":9252,"date":"2018-01-11T09:06:40","date_gmt":"2018-01-11T08:06:40","guid":{"rendered":"http:\/\/www.matematicaok.com\/?p=9252"},"modified":"2018-01-11T10:11:53","modified_gmt":"2018-01-11T09:11:53","slug":"es-246-semicirconferenza-di-diametro-ab2","status":"publish","type":"post","link":"https:\/\/www.matematicaok.com\/?p=9252","title":{"rendered":"Es. 246 – Semicirconferenza di diametro AB=2"},"content":{"rendered":"
Data la semicirconferenza di diametro AB=2, considera il punto P\u00a0appartenente a essa e tale che l’angolo PBA=x; traccia la tangente in P, e sia H la proiezione del punto B\u00a0sulla tangente.<\/div>\n
Determina la funzione f(x) = PH\u00a0+\u00a0<\/span><\/span><\/span><\/span>HB e traccia il suo grafico ed evidenzia la parte relativa al problema.<\/div>\n
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<\/div>\n","protected":false},"excerpt":{"rendered":"

Data la semicirconferenza di diametro AB=2, considera il punto P\u00a0appartenente a essa e tale che l’angolo PBA=x; traccia la tangente in P, e sia H la proiezione del punto B\u00a0sulla tangente. Determina la funzione f(x) = PH\u00a0+\u00a0HB e traccia il suo grafico ed evidenzia la parte relativa al problema.<\/p>\n","protected":false},"author":1,"featured_media":9259,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":true,"jetpack_social_options":{"image_generator_settings":{"template":"highway","enabled":false},"version":2}},"categories":[127,193,226],"tags":[],"class_list":["post-9252","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-esercizi-svolti","category-geometria-piana","category-trigonometria"],"jetpack_publicize_connections":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/www.matematicaok.com\/wp-content\/uploads\/2018\/01\/Es246_Fig.png","jetpack_shortlink":"https:\/\/wp.me\/p85Wmq-2pe","_links":{"self":[{"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/posts\/9252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=9252"}],"version-history":[{"count":3,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/posts\/9252\/revisions"}],"predecessor-version":[{"id":9261,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/posts\/9252\/revisions\/9261"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=\/wp\/v2\/media\/9259"}],"wp:attachment":[{"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=9252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=9252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.matematicaok.com\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=9252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}